What is the peak-to-peak voltage of a sine wave with an RMS voltage of 120 volts?

What is the peak-to-peak voltage of a sine wave with an RMS voltage of 120 volts?

• A. 250 volts
• B. 339.4 volts
• C. 180 volts
• D. 100 volts

Answer: (B)

The peak-to-peak voltage of a sine wave can be calculated from its RMS (Root Mean Square) voltage using the relationship between these two values. For a sine wave, the RMS voltage is equal to the peak voltage divided by the square root of 2, or mathematically, \( V_{RMS} = \frac{V_{peak}}{\sqrt{2}} \). To find the peak voltage from the RMS voltage of 120 volts, you can rearrange the formula: 1. Multiply both sides by \( \sqrt{2} \): \( V_{peak} = V_{RMS} \times \sqrt{2} \) 2. Substituting the RMS voltage into the formula gives: \( V_{peak} = 120 \, \text{volts} \times \sqrt{2} \) Using the approximate value of \( \sqrt{2} \) (about 1.414), you get: \( V_{peak} \approx 120 \times 1.414 \approx 169.68 \, \text{volts} \). The peak-to-peak voltage is then twice the peak voltage, calculated as: \( V_{pp}

The peak-to-peak voltage of a sine wave can be calculated from its RMS (Root Mean Square) voltage using the relationship between these two values. For a sine wave, the RMS voltage is equal to the peak voltage divided by the square root of 2, or mathematically, ( V_{RMS} = \frac{V_{peak}}{\sqrt{2}} ).

To find the peak voltage from the RMS voltage of 120 volts, you can rearrange the formula:

1. Multiply both sides by ( \sqrt{2} ):

( V_{peak} = V_{RMS} \times \sqrt{2} )

2. Substituting the RMS voltage into the formula gives:

( V_{peak} = 120 , \text{volts} \times \sqrt{2} )

Using the approximate value of ( \sqrt{2} ) (about 1.414), you get:

( V_{peak} \approx 120 \times 1.414 \approx 169.68 , \text{volts} ).

The peak-to-peak voltage is then twice the peak voltage, calculated as:

( V_{pp}